Java Program To Implement Divide By Zero Exception

Java won't throw an exception in the event that you partition by float zero. It will identify a run-time error just on the off chance that you separate by integer zero, not double zero. On the off chance that you separate by 0.0, the outcome will be INFINITY

Java Program To Implement Divide By Zero Exception

import java.util.Scanner;
class DivideZero
{
static public void main(String args[])
{
Scanner sc = new Scanner(System.in);
System.out.println("Enter 2 numbers : ");
int a = sc.nextInt();
int b = sc.nextInt();
try
{
System.out.println("Quotient : " + (a/b));
}
catch(ArithmeticException e)
{
System.out.println(e);
}
}
}
Output:
Enter 2 numbers :
10
0
java.lang.ArithmeticException: / by zero


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